Someone asked me to explain Q3 again. Definitely I'll explain when I will have collected sufficient inquiry that I could make 75 minutes course. Till that I explain that question again here.
Q3. What is the probability that a divisior of 10^99 is a multiple of 10^96?
Solution:
Number of total divisior of 10^99 = (99+1)^2 = 10000
In that number of multiple of 10^96 = [(99-96) +1]^2 = 16
i.e. Required Probability = 16/10000 = 1/625 .
https://unacademy.com/lesson/conditional-probability-in-hindi/EA4QAMSP
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